(y^2+y-12)/(2y^2-18)

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Solution for (y^2+y-12)/(2y^2-18) equation:


D( y )

2*y^2-18 = 0

2*y^2-18 = 0

2*y^2-18 = 0

2*y^2 = 18 // : 2

y^2 = 9

y^2 = 9 // ^ 1/2

abs(y) = 3

y = 3 or y = -3

y in (-oo:-3) U (-3:3) U (3:+oo)

(y^2+y-12)/(2*y^2-18) = 0

y^2+y-12 = 0

y^2+y-12 = 0

DELTA = 1^2-(-12*1*4)

DELTA = 49

DELTA > 0

y = (49^(1/2)-1)/(1*2) or y = (-49^(1/2)-1)/(1*2)

y = 3 or y = -4

(y+4)*(y-3) = 0

((y+4)*(y-3))/(2*y^2-18) = 0

( y+4 )

y+4 = 0 // - 4

y = -4

( y-3 )

y-3 = 0 // + 3

y = 3

y in { 3}

y = -4

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